Question

Find the largest number which divides 2271,3079 and 3355 leaving remainder ś 10,20 and 30 respectively

Answer 1

Answer:

1. 227.
2. 308.
3. 333.

make me as braniliest. please please..........

Answer 2

Answer:

Hi,

here,give that,

2271,3079 and 3355 that leaving remainder 10, 20, 30.

now,

(2271 -10) = 2261

(3079 -20) = 3059

(3355 -30) = 3325.

Now, we have to find the hcf ( 2261 and 3059)

HCF ( 2261 and 3059) = 133

now,

HCF ( 133 and 3325 ) = 133

So,

HCF of ( 2261 , 3059 and 3325 ) = 133

HOPE THIS HELPS YOU!!!!