Math, asked by singh956, 1 year ago

find the largest number which divides 2271 , 3079 and 3355 leaving remainder 10,20 and 30 respectively

Answers

Answered by gangwarakash999

2

MCF{(2271-10),(3079-20),(3355-30)}
MCF{2261,3059,3025}
MCF{133}
So the no is 133.

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