Question

find the largest number which divides 231 and 2310 leaving 7 as remainder in each case please solve Full answer​

Answer 1

do-7 from both of the no. and do HCF u will get answer.

Answer 2

$Given \: numbers \: 231\: and \: 2310$

$Remainder = 7$

$Required \: number =HCF \: of \: ( 231 - 7 , 2310 - 7 )$

$= HCF \: of \: ( 224 , 2303 )$

224|2303|10

*****|2240|

_________

******* 63|224|3

*********** 189

____________

************35|63|1

****************35

_____________

****************28|35|1

********************28

_________________

********************7| 28|4

***********************28

__________________

*****************(0)

$\green { HCF \:of \: ( 224,2303) = 7 }$

Therefore.,

$The\: largest\: number \: which \: divides$

$231\: and \: 2310\: leaving \:7 \:as \:remainder$

$in\: each\: case\: is \: 7$

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