Question

Find the largest number which divides 24 ,36 and 54 leaving remainder 5 in each case.

Answer 1

Answer:

The smallest number divisible by all 24, 36, 54 is = 216

Answer 2

Answer:

The smallest number divisible by all 24, 36, 54 is:

=> LCM(24, 36, 54) = 216.

Hope it helped.