Question

find the largest number which divides 245 and 1029 leaving remander 5 in each case​

Answer 1

Answer:

Step-by-step explanation:

Given :-

245 and 1029 leaving remander 5

To Find :-

The Largest Number which divides 245 and 1029

Solution :-

we have to subtract 5 from each number

245 - 5 = 240  

1029 - 5 = 1024

HC.F of 240 & 1024 by Euclid division lemma (a = bq + r)

Here, a = 1024  & b = 240

Putting all the values, we get

a = bq + r

⇒ 1024 = 240 × 4 + 64

⇒ 240 = 64 × 3 + 48

⇒ 64 = 48 × 1 + 16

⇒ 48 = 16 × 3 + 0

H.C.F is 16

Hence, the required number is 16.

Answer 2

Answer:

The required number is 16

Step-by-step explanation:

Given that:

245 and 1029 both of these numbers give reminder 5.

Now,

we have to find out the largest number which divides 245 and 1029.

So that,

first we have to subtract 5 from both these numbers are 245 and 1029.

=> 245 - 5 = 240

and

=> 1029 - 5 = 1024

Now,

find the HCF of 240 and 1024 by the help of Euclid's division lemma method.

As we know that the formula of euclid's division lemma is:

[ a = bq + r ]

Given,

a = 1024

b = 240

Putting the given values

a = bq + r

=> 1024 = 240 × 4 + 64

=> 240 = 64 × 3 + 48

=> 64 = 48 × 1 + 16

=> 48 = 16 × 3 + 0

.°. HCF = 16

Therefore, the required number is 16.