find the largest number which divides 245 and 1029 leaving remainder 5 in each case
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so lets subtract 5 from 245 and 1029 at beginning itself.
1029 - 5 = 1024.
245 - 5 = 240
now by euclid lemma division,
1024 = 240 × 4 + 64
240 = 64 × 3 + 48
64 = 48 × 1 + 16
48 = 16 × 3 + 0
hence the required number is 16.
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