Question

find the largest number which divides 248 and 1032 by leaving remainder 8 in each case

Answer 1

The number will be the HCF of 248-8 and 1032-8.

240=2*2*2*2*3*5

1024=2*2*2*2*2*2*2*2*2*2

So HCF of 240 and 1024= 2*2*2*2=16

So 16 is the required answer.

Answer 2

For this first of all reduce 8 from these numbers--------> 248-8=240........ 1032-8= 1024......... Largest number which divides 248 and 1032 by leaving remainder 8 in each case= H.C.F. of 240 & 1024........... 240= 2×2×2×2×3×5........... 1024= 2×2×2×2×2×2×2×2×2×2............ Now, common factors are------> 2,2,2,2, so H.C.F.= 2×2×2×2= 16..... So the answer is 16...