Question

Find the largest number which divides 302 and
327 leaving remainder 6 in each case.​

Answer 1

Step-by-step explanation:

To find the largest number which divides 257 and 328 leaving remainder 6 in each case we will first subtract 6 from each number

257–6=251

328–6=322

Now find HCF of 251 and 322 by using Euclid's division lemma

322=251×1+71

251=71×3+38

71=38×1+33

38=33×1+5

33=5×6+3

5=3×1+2

3=2×1+1

2=2×1+0

So the HCF is 1.

Only 1 can divide both the numbers leaving remainder 6 in each case.