Question

Find the largest number which divides 318 and 739 leaving remainder 3 and 4 respectively​

Answer 1

Since on dividing 318 by the required no. the remainder is 3

then 318-3 ie. 315 wil be exactly divisible by the required no.

Similarly,739-4 ie. 735 will be exactly divisible by the required no.

PRIME FACTORISATION OF

315=3 * 3 * 5 * 7

735=7 * 3 * 5* 7

H.C.F OF 315 AND 735 = 3 * 5 * 7 =105

Answer 2

Answer:

the largest number which divides 318 and 739 leaving remainder 3 and 4 is 105

Step-by-step explanation:

firstly we will subtract 3 and 4 from 318 and 739 to get the hcf of those new number.....

318-3=315, 739-4=735

we will find hcf of (315,735)

by Euclid's division algorithm,

735=315*2+105

315=105*3+0

HCF = 105

answer: largest number which divides 318 and 739 leaving remainder 3 and 4 is 105.............

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