Question

find the largest number which divides 320 and 457 and leaves remainder 6​

Answer 1

Hey mate,

To find the largest number which when divides 320 and 457 leaving the remainders 6 respectively. First we subtract the remainders from the given numbers and then calculate the HCF of New numbers.

Given numbers are 320 & 457 and remainders are 6.Then new numbers after Subtracting remainders are :(320 - 6) = 314 and (457- 6)= 451

We have to find the HCF of 314and 451 by using Euclid's division Lemma, a= bq+r

Here, 451>314

451= 314 x 1 + 137

314= 137 x 2 +40

137= 40 x 3 + 17

40=17×2+6

17=6×2+5

6=5×1+1

5=1×5+0

Therefore HCF of 451 & 314 is 5.

Hope it will help you

Answer 2

$\fcolorbox{pink}{aqua}{ANSWER}$

⭕️NO. LEAVING REMAINDER 6=314

⭕️NO.LEAVING REMAINDER 6=451

HCF(314,451)=

HCF(314,451)=451=314*1+137

HCF(314,451)=451=314*1+137314=137*2+40

HCF(314,451)=451=314*1+137314=137*2+40137=40*4+17

HCF(314,451)=451=314*1+137314=137*2+40137=40*4+1740=17*2+6

HCF(314,451)=451=314*1+137314=137*2+40137=40*4+1740=17*2+617=6*2+5

HCF(314,451)=451=314*1+137314=137*2+40137=40*4+1740=17*2+617=6*2+56=5*1+1

HCF(314,451)=451=314*1+137314=137*2+40137=40*4+1740=17*2+617=6*2+56=5*1+15=1*5+0

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