Question

find the largest number which divides 320 and 457 leaving remainder 5 and 7 respectively rs aggarwal class 10​

Answer 1

Answer:

We know that the required number divides 315 (320 – 5) and 450 (457 – 7). On applying Euclid's lemma, we get: Therefore, the HCF of 315 and 450 is 45. Hence, the required number is 45.

Step-by-step explanation:

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Answer 2

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The largest number which divides 320 and 457 leaving remainder 5 and 7 respectively is

= LCM OF (320-5) & (457-7)

= LCM OF 315 & 450

Now

$315 = 3 \times 3 \times 5 \times 7$

$450 =2 \times 3 \times 3 \times 5 \times 5$

$lcm \: = 3 \times 3 \times 5 = 45$

Hence The largest number which divides 320 and 457 leaving remainder 5 and 7 respectively is 45

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