Question

Find the largest number which divides 438 & 606 leaving remainder 6 in each case.

Answer 1

we have to find HCF OF (438-6) and (606-6)
=432 and 600
here 600>432
= 600 = 432*1+168
= 432 = 168*2+96
= 168 = 96*1+72
= 96 = 72*1+24
=72 = 24*3+0
here the remainder becomes 0 so HCF is 24

Answer 2

Answer:

The largest number obtained is 24.

Solution:

Let the largest no. be x

Given,

438, when divided by x gives remainder 6.

∴ (438-6) i.e.432 is divisible by x.

606, when divided by x gives remainder 6.

∴ (606-6) i.e.600 is divisible by x.

Hence, x will be the H.C.F of 432 and 600.

Using continuous division method, H.C.F of 432 and 600 is given by:

The largest number obtained is 24.