Question

Find the largest number which divides 438 and 606 leaving remainder 6 in each case .

Answer 1

Given that the largest number which divides 438 and 606 leaving remainder 6.
We need to deduct the remainder 6 from both the cases.

438 - 6 = 432

606 - 6 = 600.

Therefore HCF of 432 and 600 gives us the largest number remainder that gives remainder 6.

Prime factorization of 432 = 2 * 2 * 2 * 2 * 3 * 3 * 

Prime factorization of 600 = 2 * 2 * 2 * 3 * 5 * 5

HCF(432,600) = 2 * 2 * 2 * 3

                         = 24.



Hence the largest number is 24 that divides 438 and 600 leaving remainder 6.


Hope this helps!

Answer 2

Step-by-step explanation:

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