Find the largest number which divides 461 and 90 leaving remainder 6in each case
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7 is largest number which divides 461 and remainder 6
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461-6 = 45
90-6 = 84
455=84x5+35
84=35x2+4
35=14x2+7
14=7x2+0
HFC=7
Therefore the largest number which divides 461 and 90 is 7
90-6 = 84
455=84x5+35
84=35x2+4
35=14x2+7
14=7x2+0
HFC=7
Therefore the largest number which divides 461 and 90 is 7
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