find the largest number which divides 546and 764,leaving remainder 6and 8 respectively.
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Answered by
4
soln.
to find HCF of
546-6=540 764-8=756
By euclids division lemma
a=bq+r, 0
756=540 X 1 + 216
540=216 X 2 + 108
216=108 X 2 + 0
therefore, HCF of 540, 756 is 108
to find HCF of
546-6=540 764-8=756
By euclids division lemma
a=bq+r, 0
756=540 X 1 + 216
540=216 X 2 + 108
216=108 X 2 + 0
therefore, HCF of 540, 756 is 108
Answered by
2
Subtract 6 from 546 and 8 from 764.. and find the H.C.F of them ..and hence that’s your answer..
Anyways your answer in simple is = 108.
Hope it helps..
Anyways your answer in simple is = 108.
Hope it helps..
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