find the largest number which divides 60 and 963 leaving the remainder 6 in each case
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Hey dear friend!
Here is your answer
First substract the remainder from the given number
60-6 => 54
963-6 => 957
Now find the HCF
54=> 2×3×3×3
957=> 3×11×29
So the HCF is 3
The largest number 3 is whose remainder 6
Here is your answer
First substract the remainder from the given number
60-6 => 54
963-6 => 957
Now find the HCF
54=> 2×3×3×3
957=> 3×11×29
So the HCF is 3
The largest number 3 is whose remainder 6
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