Math, asked by amit50150, 1 year ago

find the largest number which divides 615 and 936 leaving remainder 6 in each case​

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Answered by adityasoni66
2

Answer:

It is given that required number when divides 615 and 963, the remainder is 6 in each case. ⇒ 615 - 6 = 609 and 963 - 6 = 957 are completely divisible by the required number

Answered by SyedNomanShah
1

Answer:

Hope its helpful for you.....

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