find the largest number which divides 615 and 963 leaving remainder 6 in each case
Answers
Answered by
0
Answer:
87
Step-by-step explanation:
find the HCF to get answer which is 87
615/87= 7 6/87
973/87= 11 6/87
7×87+6=615
11×87+6=963
Answered by
0
Answer:
58
Step-by-step explanation:
615-6=609 963-6=957
2 x 609--957= 203--319
29 x 203--319= 7--11
29 x 2= 58
HCF=58
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