Math, asked by dg8105624, 7 months ago

find the largest number which divides 615 and 963 leaving remainder 6 in each case​

Answers

Answered by crumble
0

Answer:

87

Step-by-step explanation:

find the HCF to get answer which is 87

615/87= 7 6/87

973/87= 11 6/87

7×87+6=615

11×87+6=963

Answered by jlikithgopal
0

Answer:

58

Step-by-step explanation:

615-6=609 963-6=957

2 x 609--957= 203--319

29 x 203--319= 7--11

29 x 2= 58

HCF=58

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