find the largest number which divides 615 and 963 leaving remainder 6 in each case
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Answered by
4
answer = Hcf (615-6,963-6)= hcf ( 609,957) = 3 . therefore 3 is the answer.
charu63:
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Answered by
27
Given numbers : 615, 963
Remainders for each case: 6,6
So the largest number =HCF(963-6,615-6)
=HCF(957,609)
By EDL,
957=609*1+348
609=348*1+261
348=261*1+87
261=87*3+0
So HCF=87
The largest such number is 87.
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Remainders for each case: 6,6
So the largest number =HCF(963-6,615-6)
=HCF(957,609)
By EDL,
957=609*1+348
609=348*1+261
348=261*1+87
261=87*3+0
So HCF=87
The largest such number is 87.
Hope Helped
And if helped so plz mark as brainliest....
thnx sis
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