Question

find the largest number which divides 615 and 963 leaving remainder 6 in each case​

Answer 1

Answer:

87

Step-by-step explanation:

let the divisor be X

615/X & 963/X

615 - 6 = 609 & 963 - 6 = 957  -{ Dividend - remainder}

LCM of 609 = 3, 7, 29, 87

and 957 = 3, 11, 29, 33, 87

we can see that LCM of 609 & 957 has largest common factor that is 87

The required is the HCF of the following:

615 - 6 = 609 & 963 - 6 = 957

HCF (609, 957) = 87

Therefore the largest number is 87.

if my answer is helpful please give me the brainliest