Question

Find the largest number which divides 615 and 963 leaving remainder 6 in each case.

Answer 1

SOLUTION :

To find the largest number which divides 615 and 963 leaving remainder 6 in each case.

First ,we subtracted the remainders from the given numbers and then calculate the HCF of new numbers.

Given numbers are 615 and 963 and remainder 6. Then new numbers after Subtracting remainder are :

615 -  6 = 609 and 963 - 6 = 957

The new numbers are 609 and 957.

Here, 957 > 609

By applying Euclid’s division lemma

957 = 609 x 1+ 348

609 = 348 x 1 + 261

348 = 216 x 1 + 87

261 = 87 x 3 + 0.

Here, remainder = 0

Since,the remainder has now become zero and the last divisor is 87.

Therefore, H.C.F. of  957 &  609 is 87

Hence, the required largest number is 87

HOPE THIS ANSWER WILL HELP YOU...

Answer 2

Answer:

87

Step-by-step explanation:

To find the largest number which divides 615 and 963 leaving remainder 6 in each case.

We have to find HCF.

615 = 3*3*29

963 = 3*11*29

HCF = 3*29 = 87

87 is the largest number which divides 615 and 963 leaving remainder 6 in each case.