Question

Find the largest number which divides 615 and 963 leaving remainder 6 in each case .​

Answer 1

To find the largest number which divides 615 and 963 leaving remainder 6 in each case i.e. HCF.

Consider HCF be x.

In order to make 615 and 963 completely divisible by x, we need to deduct the remainder 6 from both the cases.

609 = 3 x 3 x 29

957= 3 x 11 x 29

⇒ x = 3 x 29 = 87

∴ largest number which divides 615 and 963 leaving remainder 6 in each case is 87.

Hope it helps:)

Pls mark my answer as "Brainliest"!!!!

Answer 2

Answer:

very easy

Step-by-step explanation:

hope it is helpful