Math, asked by saketh6946, 1 year ago

Find the largest number which divides 62, 79, 132 to leave remainders 8, 7, and 6 respectively

Answers

Answered by mysticd
11
Hi ,

Find ,

( Given number - remainder )

62 - 8 = 54

79 - 7 = 72

132 - 6 = 126

Representing 54 , 72 , 126 as product

of prime,

54 = 2 × 3 × 3 × 3

72 = 2 × 2 × 2 × 3 ×3

126 = 2 × 3 × 3 × 7

Therefore ,

Required number = HCF(54 ,72 ,126 )

= 2 × 3 × 3

= 18

I hope this helps you.


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