Find the largest number which divides 62, 79, 132 to leave remainders 8, 7, and 6 respectively
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Hi ,
Find ,
( Given number - remainder )
62 - 8 = 54
79 - 7 = 72
132 - 6 = 126
Representing 54 , 72 , 126 as product
of prime,
54 = 2 × 3 × 3 × 3
72 = 2 × 2 × 2 × 3 ×3
126 = 2 × 3 × 3 × 7
Therefore ,
Required number = HCF(54 ,72 ,126 )
= 2 × 3 × 3
= 18
I hope this helps you.
Find ,
( Given number - remainder )
62 - 8 = 54
79 - 7 = 72
132 - 6 = 126
Representing 54 , 72 , 126 as product
of prime,
54 = 2 × 3 × 3 × 3
72 = 2 × 2 × 2 × 3 ×3
126 = 2 × 3 × 3 × 7
Therefore ,
Required number = HCF(54 ,72 ,126 )
= 2 × 3 × 3
= 18
I hope this helps you.
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