FIND THE LARGEST NUMBER WHICH DIVIDES 630 AND 940 LEAVING REMAINDERS 6 AND 4 RESPECTIVELY. PLEASE GIVE THE CORRECT ANSWER IF YOU DON'T I WILL REPORT YOU IF YOU GIVE THE CORRECT ANSWER I WILL MARK YOU BRAINLIEST, GIVE 15 PTS AND 5 STAR RATING ALONG WITH A THANKS. THANK YOU!!!
Answers
Answer:
312
Step-by-step explanation:
630 - 6 = 624
940 - 4 = 936
Then,
936 ÷ 624 = 1 with remainder 312
624 ÷ 312 = 2 with remainder 0
So,the answer is 312
Given : Two numbers 630 & 940 .
To find : Largest number Which on dividing 630 & 940 leaves remainder 6 & 4 respectively
Solution:
Let say Largest number = N
630 = AN + 6 => AN = 624
940 = BN + 4 => BN = 936
=> N is the HCF of 624 & 936
624 = 2 * 2 * 2 * 2 * 3 * 13
936 = 2 * 2 * 2 * 3 * 3 * 13
HCF = 2 * 2 * 2 * 3 * 13 = 312
312 is the Largest number
Verification
630 = 312 * 2 + 6
940 = 312 * 3 + 4
312 is the Largest number Which on dividing 630 & 940 leaves remainder 6 & 4respectively
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