Find the largest number which divides 630 and 940 leaving remainders 6 and 4 respectively
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Answered by
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The answer is 312 because
630 - 6 = 624
940 - 4 = 936
Then,
936 ÷ 624 = 1 with remainder 312
624 ÷ 312 = 2 with remainder 0
So,the answer is 312
630 - 6 = 624
940 - 4 = 936
Then,
936 ÷ 624 = 1 with remainder 312
624 ÷ 312 = 2 with remainder 0
So,the answer is 312
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