find the largest number which divides 69 and 124 leaving remainders 4 and 7 respectively
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Answer:
13
Step-by-step explanation:
Given numbers are 69 and 124 and remainders are 4 and 7 respectively. Then new numbers after subtracting remainders are :
69 – 4 = 65
124 – 7 = 117
The required number is HCF of 65 and 117.
HCF by prime factorization method :
Prime factorization of 65 = 5 × 13
Prime factorization of 117 = 3×3×13= = 3²×13
HCF of 65 and 117 = 13
[HCF of two or more numbers = product of the smallest power of each common prime factor involved in the numbers.]
HCF of 69 and 117 is 13.
Hence, the required greatest number which divides 69 and 124 leaving remainders 4 and 7 respectively is 13.
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