Math, asked by kumkum05, 1 year ago

Find the largest number which divides 71 and 120, leaving remainders 6 and 3, respectively.

Answers

Answered by aditi252
5
this is your answer..
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Answered by locomaniac
7
aloha user!!
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in order to find the largest number which divides 71 and 120 leaving remainders 6 and 3 we are going to subtract 6 from 71 and 3 from 120.

71 - 6 => 65 ---------(1)
120 - 3  => 117 ----------- (2)

now we are going to find out the H.C.F of (1) & (2).

65=> 5 × 13
117 => 3 × 3 × 13

H.C.F => 13 

so, 13 is the largest number which divides 71 and 120 leaving remainders 6 and 3 respectively.

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peace out !!
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