Question

Find the largest number which divides 963 and 615 leaving a remainder 6 in each case


class 10
with explanation
MATHS

Answer 1

Step-by-step explanation:

hey!

first subract 6 so that numbers are obtained find HCF of because HCF means greatest common factors so, we get 87

therefore largest number which divides both 615,963 is 87

Answer 2

Answer:

87

Step-by-step explanation:

we have to  find the largest number which divide 615 and 963 leaving remainder 6 in each case.

let the hcf be A

=> so let us subtract 6 fom both the cases

=>615 - 6 = 609

=> 963-6 = 957

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now lets find the hcf 

=>prime factorisation of 609 = 29*3*3

prime factoristaion of 957 = 29*3*11

now lets take out the common factors from both the cases

=> 29 and 3

x = 29 * 3 = 87

∴87 is the number which will divide 615 and 963 leaving remainder 6 in each case.

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hope it helps u.........