Question

find the largest number which divisible by 613 and 963 leaving remainder 6 in each case

Answer 1

Let the number be x.
$613 = x \times k + 6 \\ 607 = x \times k \\ \\ 963 = x \times q + 6 \\ 957 = x \times q$
In other words, we have to find the largest number x that divides both 957 and 607, or we have to find the HCF of 957 and 607.

This is left to you!!!

Answer 2

Answer:

Hope its helpful for you.....