Find the largest number which exactly divide 280 and 1245 leaving remainder 4 and 3 respectively
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Here is your answer
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Firstly, let us subtract the numbers:
⇒ 280 - 4 = 276
⇒ 1245 - 3 = 1242.
Now, let us find the HCF of 276 and 1242:
⇒ The factors of 276 are: 1, 2, 3, 4, 6, 12, 23, 46, 69, 92, 138, 276
⇒ The factors of 1242 are: 1, 2, 3, 6, 9, 18, 23, 27, 46, 54, 69, 138, 207, 414, 621, 1242
Thus, the HCF is 138.
The largest number that can exactly divide 280 and 1245 leaving remainder 4 and 3 respectively is 138.
_____________________________________________________________
HOPE THIS HELPS YOU :)
___________
Here is your answer
__________________
Firstly, let us subtract the numbers:
⇒ 280 - 4 = 276
⇒ 1245 - 3 = 1242.
Now, let us find the HCF of 276 and 1242:
⇒ The factors of 276 are: 1, 2, 3, 4, 6, 12, 23, 46, 69, 92, 138, 276
⇒ The factors of 1242 are: 1, 2, 3, 6, 9, 18, 23, 27, 46, 54, 69, 138, 207, 414, 621, 1242
Thus, the HCF is 138.
The largest number that can exactly divide 280 and 1245 leaving remainder 4 and 3 respectively is 138.
_____________________________________________________________
HOPE THIS HELPS YOU :)
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