find the largest number which exactly divides 280 and 12 and 5 leaving remainder 4 and 3
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280-4=276
12-3=9
276=9×30+6
9=6×1+3
6=3×2
again
5=3×1+2
3=2×1+1
2=2×1+0
then largest number =1
12-3=9
276=9×30+6
9=6×1+3
6=3×2
again
5=3×1+2
3=2×1+1
2=2×1+0
then largest number =1
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