Find the largest number which exactly divides 280 and 1245 leaving remainders 4 and 3 respectively? answer with full process and no spamming
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Answered by
5
To find the largest number which exactly divides 280 and 1245 living remainders 4 and 3 respectively, we subtract 4 and 3 from 280 and 1245.
280 - 4 = 276
1245 - 3 = 1242
276 = 2 x 2 x 3 x 23
1242 = 2 x 3 x 3 x 3 x 23
HCF = 2 x 3 x 23 = 138
Therefore, the largest number which exactly devides 280 and 1245 living remainders 4 and 3 respectively is 138.
280 - 4 = 276
1245 - 3 = 1242
276 = 2 x 2 x 3 x 23
1242 = 2 x 3 x 3 x 3 x 23
HCF = 2 x 3 x 23 = 138
Therefore, the largest number which exactly devides 280 and 1245 living remainders 4 and 3 respectively is 138.
Answered by
1
first,we subtract 4 and 3 to 280,1245
280-4=276
1245-3=1242
276=2×3×23
1242=2×3×3×3×23
HCF=2×3×23=138
280-4=276
1245-3=1242
276=2×3×23
1242=2×3×3×3×23
HCF=2×3×23=138
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