find the largest number which exactly divides 280 and 1245 leaving remainder 4 and 3
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Hi friend,
280 - 4 = 276
1245 -3 = 1242
The largest Number which is exactly divides 276 and 1242 = HCF of 276 and 1242
Prime factorisation of 276 = 2×2×3×23
Prime factorisation of 1242 = 2×3×3×3×23
Therefore,
HCF of 276 and 1242 = 2×3×23 = 138
HOPE IT WILL HELP YOU...... :-)
280 - 4 = 276
1245 -3 = 1242
The largest Number which is exactly divides 276 and 1242 = HCF of 276 and 1242
Prime factorisation of 276 = 2×2×3×23
Prime factorisation of 1242 = 2×3×3×3×23
Therefore,
HCF of 276 and 1242 = 2×3×23 = 138
HOPE IT WILL HELP YOU...... :-)
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