find the largest number which exactly divides 280 and 1245 leaving remainder 4 and 3 respectiely.
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Answered by
317
we subtract 4 and 3 from 280 and 1245.
280 - 4 = 276
1245 - 3 = 1242
276 = 2 x 2 x 3 x 23
1242 = 2 x 3 x 3 x 3 x 23
HCF = 2 x 3 x 23 = 138
∴138
280 - 4 = 276
1245 - 3 = 1242
276 = 2 x 2 x 3 x 23
1242 = 2 x 3 x 3 x 3 x 23
HCF = 2 x 3 x 23 = 138
∴138
Answered by
49
Answer:To find the largest number which exactly divides 280 and 1245 living remainders 4 and 3 respectively, we subtract 4 and 3 from 280 and 1245. 280 - 4 = 276 1245 - 3 = 1242 276 = 2 x 2 x 3 x 23 1242 = 2 x 3 x 3 x 3 x 23 HCF = 2 x 3 x 23 = 138 Therefore, the largest number which exactly devides 280 and 1245 living remainders 4 and 3 respectively is 138.
Step-by-step explanation:
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