find the largest number which exactly divides 612 and 960 leaving remainder 3 in each case
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5
Answer:
87
Step-by-step explanation:
To find the no. follow the steps -
subtract 3 from both the numbers
612 - 3 = 609
960 - 3 = 957
Hcf of 612 and 957 is 87
So the number that exactly divides 612 and 960 leaving the remainder 3 is 87
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