Find the largest number which on dividing 70 and 125 leaves remainders 5 and 8
respectively
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Answered by
0
Answer:
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Step-by-step explanation:
Number when divides 70 and 125 leaves remainders 5 and 8, then
70 - 5 = 65
125 - 8 = 117
The H.C.F of 65 and 117 is,
65 = 5 * 13
117 = 3 * 3 * 13
Hence, HCF of 65 and 117 is 13.
13 is the largest number which divides 70 and 125 and leaves remainders 5 and 8.
Answered by
0
Step-by-step explanation:
=>70-5=65
=>125-8=117
H.C.F of 65 and 117:
65=5*13
117=3*3*13
=> H.C.F =13
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