Question

find the largest number which when divided by 20, 25, 30 and 36 leaves a remainder 4 in each case.

Answer 1

First of all find LCM of 20, 25, 30, 36
Prime factors of 20 = 2 × 2 × 5
prime factors of 25 = 5 × 5
prime factors of 30 = 2 × 3 × 5
prime factors of 36 = 2 × 2 × 3 × 3
Now, LCM = 2² × 3² × 5² = 4 × 9 × 25 = 900

900 is the largest number which is divisible by 20, 25, 30 and 36 .
Now, when we add 4 with 900 , it will leave remainder 4 in each case .
∴ largest number = 900 + 4 = 904

Hence, answer is 904

Answer 2

Answer:

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