Math, asked by tingu3, 1 year ago

find the largest number which will divide 398 and 436 leaving remainder 11 and 15 respectively

Answers

Answered by shreyasbejoy00
27

Answer:


Step-by-step explanation:

398-11 is equal to387

436-15 is 421

Then find hcf of two new number we got

Hcf is 1

Answered by Anonymous
0

Given :-

398 , 436 and 542

To Find :-

The largest number

Solution :-

Let’s assume the integer is x

According to the condition given in the question

⇒ xy+7 = 398

⇒  xz+11 = 436

⇒  xk+15 = 542

⇒ xy =391

⇒  xz = 425

⇒  xk = 527

⇒  17 × 23 = 391

⇒  17 × 25 = 425

⇒ 17 × 31 = 527

So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.

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