find the largest number which will divide 398 and 436 leaving remainder 11 and 15 respectively
Answers
Answered by
27
Answer:
Step-by-step explanation:
398-11 is equal to387
436-15 is 421
Then find hcf of two new number we got
Hcf is 1
Answered by
0
Given :-
398 , 436 and 542
To Find :-
The largest number
Solution :-
Let’s assume the integer is x
According to the condition given in the question
⇒ xy+7 = 398
⇒ xz+11 = 436
⇒ xk+15 = 542
⇒ xy =391
⇒ xz = 425
⇒ xk = 527
⇒ 17 × 23 = 391
⇒ 17 × 25 = 425
⇒ 17 × 31 = 527
So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.
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