Question

find the largest perfect square number that is smaller than the largest 6 digit number

Answer 1

Hey

Here is your answer,

Let x² be the largest six-digit perfect square. 

The largest six-digit number is 999,999, so 
x² ≤ 999,999. 

You know that 1,000² = 1,000,000, which is only 1 more than 999,999, so x² must be the next smaller square, which is (1,000 - 1)². 
(1,000 - 1)² = 999² = 998,001. 

Hope it helps you!

Answer 2

998001 is the answer,

1000^2 = 1000000 but this is greater than greatest six digit no.

999^2. = 998001 So this is the answer