Question

Find the largest positive integer that will 122, 150 and 115 leaving remainders 5,7,11 respectively.

Answer 1

Answer:

122-5=117

150-7=143

115-11=104

Step-by-step explanation:

Prime factorization of: -

117=3*3*13

104=2*2*2*13

143=13*11

HCF of 117, 104, 143=13

The largest number that divide 122, 150 and 115 leaving remainder 5, 7, 11 is 13.