Math, asked by solankem7283, 1 year ago

Find the largest positive integer that will devide 398,436, and 542 leaving reminder 7,11,15 respectively

Answers

Answered by namanguptarr
0
17 is the hcf of 398,436 and542
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Answered by Anonymous
4

Given :-

398 , 436 and 542

To Find :-

The largest number

Solution :-

Let’s assume the integer is x

According to the condition given in the question

⇒ xy+7 = 398

⇒  xz+11 = 436

⇒  xk+15 = 542

⇒ xy =391

⇒  xz = 425

⇒  xk = 527

⇒  17 × 23 = 391

⇒  17 × 25 = 425

⇒ 17 × 31 = 527

So, the largest possible integer that will divide 398,436,542 & leaves reminder 7,11 and 15 respectively was 17.

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