Find the largest positive integer that will divide 122, 150 and 115 leaving remainder 5, 7 and 11 respectively
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Answered by
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122 - 5 = 117
150 - 7 = 143
115 - 11 = 104
The HCF of 104, 117 and 143 is 13
The largest number which divides 122, 150 and 115 leaving 5, 7 and 11 respectively as remainders is 13
150 - 7 = 143
115 - 11 = 104
The HCF of 104, 117 and 143 is 13
The largest number which divides 122, 150 and 115 leaving 5, 7 and 11 respectively as remainders is 13
Answered by
1
Answer:
122 - 5 = 117
150 - 7 = 143
115 - 11 = 104
The HCF of 104, 117 and 143 is 13
The largest number which divides 122, 150 and 115 leaving 5, 7 and 11 respectively as remainders is 13
Step-by-step explanation:
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