Question

Find the largest positive integer that will divide 398,436 and 542 leaving remainders 7,11 and 15 respectively.

Answer 1

this means that
398-7=391
436-11=425
542-15=527
is exactly divisible by our required number
now find the HCF of 391 , 425 , 527
it will be 17
hence our required number is 17 which leave remainder 7 , 11 , 15 when divides 398 , 436 and 542 respectively

hope you'll be benefitted by the answer

Answer 2

It will be the hcf of:
398-7= 391

436-11= 425

542-15 = 527

so
$hcf \: of \: 391 \: 425 \: \: \: and \: 527\: is$

= 17