find the largest positive integer that will divide 434 and 539 leaving remainder 9and 12 respectively
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Answered by
8
Largest positive number will be HCF of (434-9) and (539-12)
i.e. HCF of 425 and 527
425 = 5×5×17
527=31×17
∴HCF = 17
The largest positive number will be 17
i.e. HCF of 425 and 527
425 = 5×5×17
527=31×17
∴HCF = 17
The largest positive number will be 17
Answered by
2
HEY FRIEND HERE IS UR ANSWER ,
If you divide 434, remainder is 9
So 434 - 9 = 425 is completely divisible.
And ff you divide 539, remainder is 12
So 539 - 12 = 527 is completely divisible.
Find the HCF of 425 and 527.
425 = 5×5×17
527 = 17×31
HCF = 17
So the largest possible integer is 17.
HOPE IT HELPS :)
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