Find the largest positive number that will divide 396, 434, and 540 leaving the remainder 5, 9, and 13 respectively
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Answer: 17
Step-by-step explanation:
Answer will be HCF of (396-5, 434-9, 540-13)
HCF of (391, 425, 527) = 17
Hence, the largest positive number that will divide 396, 434, and 540 leaving the remainder 5, 9, and 13 respectively is 17.
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