Math, asked by basantiparida, 1 month ago

find the largest possible 6-digit number with unique digits having 9 in the hundreds
place.

Answers

Answered by shrutimohanraj10
3

Answer:

It is simple and easy to know without any calculations.

Let ABCDEF be a 6 digit number where F is the unit/ones digit.

As stated hundreds place has 9, so D=9 . Since the digits are unique thus exclude 9 from the set 0−9 , the left numbers are 0−8 , Assign these in descending order from left to right.

876954 becomes the number that satisfies the stated conditions.

mark me brainliest please

Answered by samriddhipal5
1

Step-by-step explanation:

Come on ….

You really can do this yourself …

You clearly understand English, so what is so

dif ficult about a lit tle experiment with numbers …

Largest … (what makes a number large?)

6 digits … (clear, I hope?)

unique, so no repeats …

9 in the hundreds, so 9.

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