Question

Find the largest possible positive integer that divides 125, 162, 259 leaving remainder 5, 6 and 7 respectively. (Show proper method)

Answer 1

The nos required are,

( 125 - 5 ) = 120 , ( 162 - 6 ) = 156 and ( 259 - 7 ) = 252

(We have to find HCF because there is largest).

By prime factorization method,

120 = 2 × 2 × 2 × 3 × 5

156 = 2 × 2 × 3 × 13

252 = 2 × 2 × 3 × 3 × 7

Therefore, HCF [ 120, 156, and 252 ] = 2 × 2 × 3 = 12.

Hope it helps u mate!

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