Question

Find the largest possible positive integers that divides 125, 162 and 259 leaving remainders 5 6 and 7 respectively

Answer 1

Hey!!

Required number ( 125 - 5 ) = 120 , ( 162 - 6 ) = 156 and ( 259 - 7 ) = 252

Note:- We have to find HCF because there is largest. HCF stands for Higest Common Factor.

By prime factorization method

120 = 2 × 2 × 2 × 3 × 5

156 = 2 × 2 × 3 × 13

252 = 2 × 2 × 3 × 3 × 7

Therefore, HCF [ 120, 156, and 252 ] = 2 × 2 × 3 = 12.

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Hope it will helps you:-)

Answer 2

Hope it helps you dear friend