Find the largest possible positive integers that divides 125, 162 and 259 leaving remainders 5 6 and 7 respectively
Answers
Answered by
13
Required number ( 125 - 5 ) = 120 , ( 162 - 6 ) = 156 and ( 259 - 7 ) = 252
By prime factorization method
120 = 2 × 2 × 2 × 3 × 5
156 = 2 × 2 × 3 × 13
252 = 2 × 2 × 3 × 3 × 7
Therefore, HCF [ 120, 156, and 252 ] = 2 × 2 × 3 = 12.
Similar questions