find the largest term of the HP whose first two terms are 2/5 and 12/23 urgent
Answers
Answered by
37
if the he two term are HP are 2/5 and 12/23
there for first term of the corresponding AP is a = 5/2
and 2nd term of corresponding AP is 23/12
therefore
common difference d= 23 12 - 5 2 = 23 - 30 12 = -7 12
let the positive smallest term of AP be nth term.
therefore 5 2 + ( n - 1 ) * (-7 12 ) ≥ 0 - 7 12 * ( n - 1 )≥ - 5 2 ( n - 1 ) ≤ 5 2 * 12 7 n - 1 ≤ 30 7 = 4 . 2 n - 1 = 4 [ since n is an integern = 1 + 4 = 5 ]
fifth term of AP = 52 + ( 5 - 1 ) * (-7 12 ) = 52 - 73 = 15 - 146 = 16
largest term of HP = 5th term
therefore fifth term of HP = 6
hope this will help u
there for first term of the corresponding AP is a = 5/2
and 2nd term of corresponding AP is 23/12
therefore
common difference d= 23 12 - 5 2 = 23 - 30 12 = -7 12
let the positive smallest term of AP be nth term.
therefore 5 2 + ( n - 1 ) * (-7 12 ) ≥ 0 - 7 12 * ( n - 1 )≥ - 5 2 ( n - 1 ) ≤ 5 2 * 12 7 n - 1 ≤ 30 7 = 4 . 2 n - 1 = 4 [ since n is an integern = 1 + 4 = 5 ]
fifth term of AP = 52 + ( 5 - 1 ) * (-7 12 ) = 52 - 73 = 15 - 146 = 16
largest term of HP = 5th term
therefore fifth term of HP = 6
hope this will help u
svikram49:
if u understand every thing plz mark me as br.....
Similar questions